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Parentheses in perl find/replace

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# 1  
Old 08-19-2007
Parentheses in perl find/replace
I'm trying to use the following command to do a batch find and replace in all commonly named files through a file hierarchy

Code:
find . -name 'file' |xargs perl -pi -e 's/find/replace/g'

which works fine except for a substitution involving parenthesis.

As a specific example I'm trying to sub "G(d)" with "G('d,'p)."

The interpreter seems to just ignore the parentheses and not finding the string "Gd" simply does nothing. I can't just find/replace "d" as the character appears throughout the file.

Any help?
# 2  
Old 08-19-2007
What is the exact regular expression that you applied? It was likely not correct.
# 3  
Old 08-20-2007
"G(d)" matches the first occurance of string "Gd" and puts "d" in $1. To match string "G(d)" AS IS, use "G\(d\)"
# 4  
Old 08-21-2007
Thanks to everyone for the help.

The regex I was using was incorrect, but a little reading took care of that.
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