Comparing two files...


 
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# 8  
Old 08-07-2007
Quote:
Originally Posted by Sangal-Arun
one good logic is to ...cut and have column 2nd then 1st on each line from passwd file and redirect the output to file lets say a1. Then do the same on other passwd file and save the file as a2. Sort both file one by one and redirect output to a1sorted and a2sorted. Now run "sdiff a1sorted a2sorted"
and it will show you where we have extra members or less members..


arun
Well, I guess I'll have to settle for that. It works at least in identifying the differences. It doesn't print them out in a nice little list, but it'll have to do. If there were a way to take the names that show up in /etc/passwd, but that don't show up in the other file, and print them all out to file, that would be better. But thanks anyway!
# 9  
Old 08-07-2007
Quote:
Originally Posted by reborg
Code:
awk -F: 'FNR==NR { 
              users[$2] 
         } 
         FNR != NR { 
              if ( $1 in users ) { 
                   next 
              } else { 
                   print $1 
              }
         }' <userfile> /etc/passwd

Now that is perfect. Thanks a bunch! It works just like I need.
# 10  
Old 08-07-2007
Quote:
Originally Posted by reborg
Code:
awk -F: 'FNR==NR { 
              users[$2] 
         } 
         FNR != NR { 
              if ( $1 in users ) { 
                   next 
              } else { 
                   print $1 
              }
         }' <userfile> /etc/passwd

a slight stylistic mod:
Code:
awk -F: 'FNR==NR { 
              users[$2]
              next
         } 
         !( $1 in users ) { print $1 }' <userfile> /etc/passwd

# 11  
Old 08-07-2007
nice one Smilie much cleaner.
# 12  
Old 08-08-2007
in perl:
Code:
#!/usr/bin/perl
use strict;
use warnings;

my @pins;
open (PIN_FILE, "< pinfile")  or  die "Failed to read file pinfile : $!";
while (my $line = <PIN_FILE>) {
    push (@pins, (split (/:/, $line))[0]);
}
close (PIN_FILE);

open (PASS_FILE, "< /etc/passwd")  or  die "Failed to read /etc/passwd file : $! ";
while (my $pass_line = <PASS_FILE>) {
    my $uid = (split (/:/, $pass_line))[2];
    my $found = "no";
    foreach my $pin (@pins) {
        if ($pin eq $uid) {
            $found = "yes";
            last;  # this id is found, so stop searching further
        }
    }
    if ($found eq "no") {
        print "$uid is not found in pinfile \n $pass_line \n\n";
    }
}
close (PASS_FILE);

# 13  
Old 08-08-2007
Quote:
Originally Posted by paqman
I apologize for being such a noob at all this. But all that command seems to do is print out the contents of the users file referenced at the end.
Code:
>cat passwordfile
pin:userid:comments:
9876:clooneyg:"George Clooney,Los Angeles CA,123-123-1234":
1652:simpsonh:"Homer Simpson,Los Angeles CA,123-123-1234":

Code:
>cat userfile
pin:userid:comments:
1234:pittb:"Brad Pitt,Los Angeles CA,123-123-1234":
9876:clooneyg:"George Clooney,Los Angeles CA,123-123-1234":
6548:dansont:"Ted Danson,Los Angeles CA,123-123-1234":
9685:owenc:"Clive Owen,Los Angeles CA,123-123-1234":
1652:simpsonh:"Homer Simpson,Los Angeles CA,123-123-1234":

Code:
awk -F":" 'BEGIN{ while(getline < "passwordfile") { arr[$2]=i++ } }{ for ( i in arr ) { if ( i == $2 ) { cnt=1} } if ( cnt != 1 ) { print } cnt=0; }' userfile

Code:
1234:pittb:"Brad Pitt,Los Angeles CA,123-123-1234":
6548:dansont:"Ted Danson,Los Angeles CA,123-123-1234":
9685:owenc:"Clive Owen,Los Angeles CA,123-123-1234":

Hope this is what you had asked for!
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