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Bash while loop problem

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# 1  
Old 07-21-2007
Bash while loop problem
Hi,

I'm having a problem with the while loop in bash. I try the following script:

#!/bin/bash

while true
do
echo "test"
done

When I try this, it gives me this error:

while: Too few arguments.

What am I doing wrong?

Thanks
# 2  
Old 07-21-2007
I cannot reproduce your problem. My guess is that you are invoking the script wrong somehow so that the wrong shell is running it.

Code:
$ cat bloop
#!/usr/local/bin/bash

while true
do
echo "test"
done
$ ./bloop | head
test
test
test
test
test
test
test
test
test
test
$ csh < bloop
while: Expression Syntax.
$

# 3  
Old 07-22-2007
Thanks. I was wondering if it was something like that. I was sure I had used that same syntax before and it worked.

Thanks again.
# 4  
Old 07-22-2007
Perhaps you named your script "while"?
Last edited by kahuna; 07-22-2007 at 03:45 AM..
# 5  
Old 07-22-2007
i am a beginner in unix, and occasionally i name my scripts after a command name...i have spent hours trying to figure what is wrong before i realized its i have named that script after a command name.
# 6  
Old 07-23-2007
You're right, I named the script "while" Image

Thanks for your help!
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