syntax problem grepping?


 
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# 1  
Old 07-17-2007
syntax problem grepping?

I am calculating a time and appending a space in front of it to get only certain records in a file because the times are represented in HH:II:SS format and I don't want to see anything other than the actual hour and minute combination (hence appending the space to the front of the time). My variable line is:

GREPTIME2="' "$GREPTIME"'"

and this displays correctly on an echo:

[131]+echo GREPTIME2 = ' 06:38' <<=== (this is from a trace).

When I issue my grep statement, here's my syntax:

COUNT=`grep "$GREPTIME2" "$LBFILE" `

When I execute the script, here's what shows up in the trace:

[103]+[103]+grep ' 06:45' /mydata.log
COUNT=

Note that COUNT is equal to nothing. If I copy and paste the part of the previous statement:

grep ' 06:45' /mydata.log

and execute it from the command line, I get 135 lines (which is what I expect to get)! What am I doing wrong? I can grep from the command line and find it, but it doesn't work in the script! Help!!!
# 2  
Old 07-17-2007
Try
Code:
GREPTIME2=" $GREPTIME"

# 3  
Old 07-17-2007
So your problem here is to populate the COUNT variable with the no. of occurence of the string.

Included the count option in your grep statement

Code:
COUNT=`grep -c "$GREPTIME2" "$LBFILE" `

# 4  
Old 07-17-2007
I don't think either of the repliers understands the problem.

1) The variable actually contains the correct syntax of what I want (as seen in the trace).

2) When the grep command is executed, I am expecting to get results - I get NONE. This is where the problem is.

3) I don't need to (although I was unaware of a -c option) to use that to get a count because I am piping it to a wc -l which will give me the count (I just didn't put that in my statement as it would only confuse the issue).

As stated earlier, the grep command is NOT returning anything when executed in the script, but IS returning something when run from the command line. What is wrong?
# 5  
Old 07-17-2007
Quote:
Originally Posted by dsimpg1
I don't think either of the repliers understands the problem.

1) The variable actually contains the correct syntax of what I want (as seen in the trace).
Actually, your trace shows that you are searching for the time surrounded by single quotes. I think you want to search for the time without the quotes.

Quote:
Originally Posted by dsimpg1
2) When the grep command is executed, I am expecting to get results - I get NONE. This is where the problem is.
Which is exactly why I suggested my change. Your grep is not searching for the string you think it is.
# 6  
Old 07-17-2007
Both, Kahuna and Lorcan are right.
Your statement should be changed to:
Code:
GREPTIME2=" $GREPTIME"

And the '-c' option in the 'grep' should be used.
Quote:
(I just didn't put that in my statement as it would only confuse the issue).
Dsimpg1, the entire scenario should always be displayed to get the a full
analisys of the problem -- the solution could be in the hidden statement.
# 7  
Old 07-17-2007
Quote:
Originally Posted by dsimpg1
[131]+echo GREPTIME2 = ' 06:38' <<=== (this is from a trace).
Perhaps I am missing something, but if you'll notice, there IS a space before the quotes.

Quote:
Originally Posted by dsimpg1
When I execute the script, here's what shows up in the trace:

[103]+[103]+grep ' 06:45' /mydata.log
COUNT=
Again, there IS a space in there (as seen in both traces).

I am not understanding why it is NOT finding anything (doesn't find anything even if there is no space via the script, but DOES find it if I run it via the command line). Any ideas?
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