Shell Programming and Scripting

I have some files in a directory. The file names is as file### (Where #### is a number sequence). I want to delete all those files which have sequence less than or equal to 333 in their name.
I created a file which stores the name by using this command

ls -1r file* > list

after this I created this script to delete the files (script is pasted below)

{ while read myline;
do
varnum=$myline | cut -c5-8
echo "File name is : " $varnum
if [ "$varnum" -lt 333 ]; then
echo "Deleting : " $myline
rm $myline

fi
if [ "$varnum" -eq 333 ]; then
echo "Deleting : " $myline
rm $myline
fi

done
} < list

problem is that it is deleting all files with file###, even files which have sequence number greater tha 333. I am new to unix, may be when I am getting the sequence number from the filename, i need to cast that from string to number. If this is the case, i don't know how i can cast that. Your help will be highly appreciated. thanks

Code:

varnum=`echo $myline | cut -c5-8`

Code:

rm $( ls file* | awk ' substr($0,5) <= 333 ' )

With zsh:

Code:

rm file<-333>

Code:

rm file[012]*
rm file3[012]*
rm file33[0123]

Code:

$ touch file1 file111 file11111
$ ls file[012]*
file1  file111  file11111
$ ls file<-333>
file1  file111

Thus, as for the original specification, 'file11111' is not present in the directory.

In any event, if there are files in the same directory not meeting the requirement:

Code:

rm file[012]??
rm file3[012]?
rm file33[0123]