Shell Programming and Scripting

Hi all,
I put together a script that seems not working as I would like to and after spending hours to find the problem I decided to ask your help.
The thing I am trying to do is call AWK command on the TRUE branch of if statement. Else branch should only print out a message to screen.

This is the code I am using:


...
for printer in "$@" ; do
lpstat $printer|grep $printer |grep '-' >$TEMP_FILENAME
grep '-' $TEMP_FILENAME
status=$?
if [[$status -eq 0]] ; then
awk '
{
here I do some stuff...
}
' $TEMP_FILENAME
else
echo "No jobs in the printer queue $printer ..."
fi
done

The result I got is not what I expect:
printerjob1 user priority 0 Jun 27 08:26
printerjob2 user priority 0 Jun 28 13:38
./prg.sh[103]: [[0: not found
No jobs in the printer queue printername ...

So for me it seems program executes somehow both branches of the IF statement.
The line 103 where the problem is indicated is:
if [[$status -eq 0]] ; then

I could not solve it , so please recommend me what the problem might be...

Thank you!
BearCheese

Leave a space before $status and after 0

Code:

if [[ $status -eq 0 ]] ; then

If you have q option with grep which gives the exit status, try this

Code:

if grep -q '-' $TEMP_FILENAME ;then 
awk '
{ 
here I do some stuff...
}
' $TEMP_FILENAME