Shell Programming and Scripting

Hi,

I want to print certain fields from my data file depending on certain conditions. Somebody pls let me know how to send it to awk.

The command below is the one which I want to use in a shell script and this prints fine
cat ./datafile.dat | grep -i $SEARCH_STR | awk -F: '{ print $1 $2 $3 }'

Is there any way we can have a variable called DISP_STR and send it as follows:
DISP_STR="\$1 \$2 \$3"
cat ./datafile.dat | grep -i $SEARCH_STR | awk -F: '{ print "$DISP_STR" }'

I tried this but it fails.

Any other ways to get this accomplished is welcome. :-)

Thanks for any help provided!!
maverix

With the ":' field separator:

Code:

mPrtList="$1 $2 $3"
egrep -i "$SEARCH_STR" ./datafile.dat | awk -F: "{ print $mPrtList }"

Without the ":" field separator:

Code:

mPrtList='$1 $2 $3'
egrep -i "$SEARCH_STR" ./datafile.dat | awk -F: "{ print $mPrtList }"

Code:

DISP_STR="\$1 \$2 \$3"
SEARCH_STR=search_string
eval awk -F: \'/$SEARCH_STR/ { print $DISP_STR } \' inile

Hello Shell Life and aigles,

Thanks to both of you for your time.

mPrtList="$1 $2 $3"
egrep -i "$SEARCH_STR" ./datafile.dat | awk -F: "{ print $mPrtList }"

I had tried this earlier but this seems to print all the fields in the selected records.

The one below seems to have worked
DISP_STR="\$1 \$3 \$5"
cat ./datafile.dat | grep -i $SEARCH_STR | eval awk -F: \'/$SEARCH_STR/ { print $DISP_STR } \'

This gives out only the columns asked for.

Thanks again for the response.
cheers
maverix

Replace:

Code:

cat ./datafile.dat | grep -i $SEARCH_STR | eval awk -F: \'/$SEARCH_STR/ { print $DISP_STR } \'

by

Code:

eval awk -F: \'/$SEARCH_STR/ { print $DISP_STR } \' ./datafile.dat

Maverix,
Use the single quotes version:

Code:

mPrtList='$1 $2 $3'
egrep -i "$SEARCH_STR" ./datafile.dat | awk -F: "{ print $mPrtList }"