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# 1  
Old 06-20-2007
Question nthing question

Help! I have an array with unknown # of subscripts. When certain condition is met, I need to print out the various elements and repeat by adding 6. So output should look something like:

print "${A[1]} ${A[2]} ${A[3]}"
print "${A[7]} ${A[8]} ${A[9]}"
print "${A[13]} ${A[14]} ${A[15]}"
etc, and keep going until EOF.

I only have unix, preferrably ksh, no perl available. Any suggestions are greatly appreciated! Smilie

leslie02
# 2  
Old 06-20-2007
Leslie,
Is this what you want:
Code:
typeset -i mInd1=1
typeset -i mInd2
typeset -i mInd3
while [ ${mInd1} -le 30 ]
do
  mInd2=${mInd1}+1
  mInd3=${mInd1}+2
  print ${A[${mInd1}]} ${A[${mInd2}]} ${A[${mInd3}]}
  mInd1=${mInd1}+6
done

# 3  
Old 06-20-2007
This enumerates an array by three's:
Code:
 while (( i < ${#A[*]} ))
 do 
     echo "${A[i]} ${A[i+1]} ${A[i+2]}
     let i=i+3
done

If you are going to "refill" the array
Code:
unset A

will clear all of the entries and set length to zero
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