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grep to show lines only after pattern

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# 1  
Old 06-12-2007
grep to show lines only after pattern
When i grep for a pattern the search results comes up with matching lines(some before the pattern and some after)...how can i limit the search so that it shows only the lines after the pattern specified
# 2  
Old 06-12-2007
Quote:
Originally Posted by wannalearn
When i grep for a pattern the search results comes up with matching lines(some before the pattern and some after)...how can i limit the search so that it shows only the lines after the pattern specified
You must have provided some extra flags for grep. Show us the grep command that you issued. GNU grep talks about
Code:
       -A NUM, --after-context=NUM
              Print NUM lines of trailing context after matching lines.  Places
              a line containing -- between contiguous groups of matches.
       -B NUM, --before-context=NUM
              Print NUM lines of leading context before matching lines.  Places
              a line containing -- between contiguous groups of matches.

Surely you must be have provided both the flags.
# 3  
Old 06-12-2007
hmm..
This wont help..
Print NUM lines of trailing context after matching lines..


Instead of lines I need pattern


Eg: Say i search for a pattern abc...the result i get is hdhd fhfhfh abc hdh jdhf

I want the result to be hdh jdhf

I went through the man page for grep and couldnt find any option which would help me accomplish the above result :-(
# 4  
Old 06-12-2007
You might want to look into the -E flag to see if it helps you. Off the top of my head, I can say, you could use sed.

Code:
sed -n -e "s/.*abc \(hdh jdhf\)/\1/p" input.txt

See if it helps. You might want to tweak things a bit.
# 5  
Old 06-12-2007
nope
-E doesnt help too...

I came around with a workaround using awk -F ! :-)
# 6  
Old 10-09-2007
Hi wannalearn, I need that "awk" script that you used to print 'n' no of lines below the matching pattern including that line also.

grep -A<n> "pattern" <file> --> will do the job, though I need an awk script for this. Please provide me.
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