Little bit weired : Find files in UNIX w/o using find or where command


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# 1  
Little bit weired : Find files in UNIX w/o using find or where command

Yes , I have to find a file in unix without using any find or where commands.Any pointers for the same would be very helpful as i am beginner in shell scritping and need a solution for the same.

Thanks in advance.

Regards
Jatin Jain
# 2  
Quote:
Originally Posted by jatin.jain
Yes , I have to find a file in unix without using any find or where commands.Any pointers for the same would be very helpful as i am beginner in shell scritping and need a solution for the same.

Thanks in advance.

Regards
Jatin Jain
the only reason i guess you can't use find is you might be doing homework. but nevertheless .. if you can't use find, use locate? the other way is to use ls with -R option.

Last edited by ghostdog74; 05-26-2007 at 07:00 AM..
# 3  
Hi Ghost,
i tried using ls but how to do it recursively ls -r ?. It dint work for me
i will show u a snippet of my script

#!/bin/sh
echo $1 #display the input entered
c=$1
ls -l $c | awk `(if(NR>0) pwd)` # usinf ls command and awk i m trying to get those records and print its path,pwd is not working there
# 4  
assuming you know the file name
Code:
#!/bin/sh
ls -lR / | awk -v filename="$1" '/^\//{ dir=$0} 
                /^-/{ if ( $9 == filename ) { 
		       print "Found " filename " in "dir
		      }
		
		}'


Last edited by ghostdog74; 05-26-2007 at 07:28 AM..
# 5  
awk: syntax error near line 1
awk: bailing out near line 1
whts this
# 6  
what did you do? show your code.
# 7  
#!/bin/sh
ls -lR / | awk -v filename="$1"
'/\//{ dir=$0}
/^-/{ if ( $9 == filename ) {
print "Found : " filename " in " dir
}
}'

I think its the same as u had posted.
Let me know if here is some syntax mistake
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