Shell Programming and Scripting

Hi,

I have some files in a folder with different time stamps and
I want to display the files which are older than 1 hour.

i tried with find.

need urgent help.

Search Forum before posting ...
See move log files over 12 hours old...
and date/time


Jean-Pierre.

I have written the below ksh script(in sun solaris) using one old posting but i am getting an error message saying that " ./fileage: not found".

Looks like the fileage is not recognized.
please can any one help.

#!/bin/ksh
AGE=$1
cd c:/temp
for file in $(ls)
do
echo "in the for loop"
if [[ $(( $(./ $file)/60)) -ge $AGE ]]
then
echo $file >>outputfiles.txt
fi
done >outputfiles.txt

final=`wc -l outputfiles.txt|awk '{print $1}'`
if [ $final -ge 1 ]
then
echo $final|mailx -s "Unprocessed Files in blabla" abc.xyz@yahoo.com
else
echo "Everything's OK"
fi

I don't understand what you want to do in the following statement :

Code:

if [[ $(( $(./ $file)/60)) -ge $AGE ]]

If possible, give us examples of input files and results that you expect.

Jean-Pierre.

Folder? Do you mean directory?

If you have GNU (or FreeBSD) find:

Code:

find . -maxdepth 1 -type 5 -mmin +60

i am using sun Solaris.

i am trying to write a script which will display files from a particular folder(Directory)(should not include subdirectories) which are 2 hrs(this should be used like a variable so that i can change the time) older.

i tried using find command. but find looks in subdirectories also. I don't want to check in subdirectories.

files looks like:
12345600000.PDF
32455664647.XLS

appriciate your help.

use prune option with find