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Search for string and display those NOT found

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# 15  
Old 05-22-2007
Your problem comes from le END action, a variable is misspelled
Your program:
Code:
END {
   for (str in strings_found)
      if (string_found[str] == 0) print str;
}

instead
Code:
END {
   for (str in string_found)
      if (string_found[str] == 0) print str;
}

The initialization of the variable strings_count misses in my code, this can only affect the performances.
Code:
FNR==1 {
   strings_count=0;
   for (str in string_found) {
      if (string_found[str] == 0) {
         strings[str]++;
         strings_count++;
      }
   }
   if (strings_count == 0) exit;
}


Jean-Pierre.
# 16  
Old 05-22-2007
Jean-Pierre,
It works!!! Thank you so very much. Have a great day.

John
# 17  
Old 05-22-2007
Jean_Pierre,
I am finding that because of the size of the directory and it's sub-directories this is taking a very long time to run.

When I run a ksh script I can put a echo command in to display a variable so I know where the script is in it's run sequence. How can I do the same here? Maybe have it display which search string it is presently working on.

Thanks, John
# 18  
Old 05-22-2007
You can add the two printf statements in the program.
The informations are displayed on stderr.

Code:
#
# New data file.
# Build array with strings not yet found
#

FNR==1 {
   printf("File %s ...\n", FILENAME") | "cat >&2";
   strings_count = 0;
   for (str in string_found) {
      if (string_found[str] == 0) {
         strings[str]++;
         strings_count++;
      }
   }
   if (strings_count == 0) exit;
}

#
# Input data;
# Search data for strings not yet found
#

{
   for (str in strings) {
      if ($0 ~ str) {
         printf("  String found: %s\n", str) | "cat >&2";
         string_found[str]++;
         delete strings[str];
         if (--strings_count == 0) exit;
      }
   }
}

Jean-Pierre.
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