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Shell Programming and Scripting

to find numbers in a string

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# 1  
Old 05-16-2007
to find numbers in a string
I writing my script and got stuck in this function. Can someone help me?
I need to extract out the numbers inside a string.
Ex:
INPUT -> OUTPUT
abcdef123 -> 123
abc123def -> 123
123abcdef -> 123
a123bc45d -> 123 45
abcdefghi -> -1

Thank you!
# 2  
Old 05-16-2007
Code:
sed "s/[^0-9]//g;s/^$/-1/;" filename

# 3  
Old 05-16-2007
one way
Code:
echo "salkf4243lsfk" | tr -d '[[:alpha:]]' #or [a-z]

or in bash
Code:
#s="slfk32432sdf"
#echo ${s//[a-zA-Z]/} # or [!0-9]

# 4  
Old 05-16-2007
Thanks all!
It works.
But how can we separate each numbers?
Anyway it's fine to me!
# 5  
Old 05-16-2007
Quote:
Originally Posted by fongthai
Thanks all!
It works.
But how can we separate each numbers?
Anyway it's fine to me!
Code:
sed "s/[^0-9]*\([0-9][0-9]*\)[^0-9]*/ \1 /g;s/^[^0-9][^0-9]*$/-1/" filename

# 6  
Old 05-16-2007
Code:
awk '{ gsub(/[[:alpha:]]|[[:punct:]]/," ")}1' file

# 7  
Old 11-22-2007
Hi I have a similar problem, I would like to get a number that falls within a range from a string.

ex. input: "abcd 9034 efg 1234 hi"
output: 9034

I would only want to get the number range from 9000-9999

I've tried to use sed/grep to get what I want for hours but not able to do it, can anyone advice on this? Thanks a lot!!!
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