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Shell Programming and Scripting

to find numbers in a string

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# 8  
Old 11-22-2007
Code:
grep  '^9[0-9][0-9][0-9]$' <(printf "%s\n" $s)

Or GNU grep:

Code:
grep -oE '\b9[0-9]{3}\b' <(printf "$s")

# 9  
Old 11-22-2007
Quote:
Originally Posted by radoulov
Code:
grep  '^9[0-9][0-9][0-9]$' <(printf "%s\n" $s)

Or GNU grep:

Code:
grep -oE '\b9[0-9]{3}\b' <(printf "$s")

I tried

Code:
grep '^9[0-9][0-9][0-9]$' <( printf "%s\n", "9012 abc" )

But it returns "Missing name for redirect."
# 10  
Old 11-22-2007
and doesn't grep only grep the whole line?
# 11  
Old 11-22-2007
Quote:
Originally Posted by fayya
I tried

Code:
grep '^9[0-9][0-9][0-9]$' <( printf "%s\n", "9012 abc" )

But it returns "Missing name for redirect."
I didn't quote the variable in that example.

Code:
grep '^9[0-9][0-9][0-9]$' <( printf "%s\n", 9012 abc )

For older shells:

Code:
printf "%s\n", 9012 abc|grep '^9[0-9][0-9][0-9]$'

# 12  
Old 11-22-2007
Thanks radoulov!! Really appreciate your help! It worked great.

I always use echo, I just wonder why echo doesn't work like printf, I tried

Code:
echo "9012 abc"|grep '^9[0-9][0-9][0-9]$'

# 13  
Old 11-22-2007
Quote:
Originally Posted by fayya
Thanks radoulov!! Really appreciate your help! It worked great.

I always use echo, I just wonder why echo doesn't work like printf, I tried

Code:
echo "9012 abc"|grep '^9[0-9][0-9][0-9]$'

Because you need the newline between the words (\n).

You can do it with GNU grep:

Code:
zsh-4.3.4-dev-2% echo "9012 abc 99999"|grep -Eo '\b9[0-9][0-9][0-9]\b'  
9012
zsh-4.3.4-dev-2% echo "9012 abc 99999"|grep -Eo '9[0-9][0-9][0-9]'  
9012
9999

Last edited by radoulov; 11-22-2007 at 04:39 PM..
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