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Regular Expressions - Total beginner

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# 1  
Old 05-03-2007
Data Regular Expressions - Total beginner
Hi all, am a total beginner and need a hand getting a regular expression to work.

Basically I have a file of hits in the format:

136.120.16.32 Tue Nov 22 12:55:33 GMT 2005

and I need a regular expression so that when a user enters say:

Tue Nov 22 2005

I can grep a load of files for that date with the variable $DATEENTERED, I cant get a reg exp to ignore the time in between the date and year though. Smilie

So far i have:

grep -c "$DATEENTERED" *.hits

Many Thanks,

Adam
# 2  
Old 05-03-2007
Quote:
Originally Posted by MrAd
Hi all, am a total beginner and need a hand getting a regular expression to work.

Basically I have a file of hits in the format:

136.120.16.32 Tue Nov 22 12:55:33 GMT 2005

and I need a regular expression so that when a user enters say:

Tue Nov 22 2005

I can grep a load of files for that date with the variable $DATEENTERED, I cant get a reg exp to ignore the time in between the date and year though. Smilie

So far i have:

grep -c "$DATEENTERED" *.hits

Code:
printf "%s: " "Please enter date in DDD MMM DD YYYY format"
read wkday month year day
grep '$wkday $month .* $year' *.hits

# 3  
Old 05-03-2007
MySQL
Ah thanks very much, I was just playing with doing it the long way with awk but that is a lot easier. Why is it that I have to use double quotes when using reg exps as opposed to single? They dont work otherwise. Using ubuntu 7.04 bash.
# 4  
Old 05-03-2007
Quote:
Originally Posted by MrAd
Ah thanks very much, I was just playing with doing it the long way with awk but that is a lot easier. Why is it that I have to use double quotes when using reg exps as opposed to single? They dont work otherwise. Using ubuntu 7.04 bash.

It has nothing to do with regexps; a variable is not expanded inside single quotes.

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