Awk scripting and usage of regex to locate a hyperlink
Hello guys,
I need to write awk script that would take an html page and output a list of each unique http link on that webpage followed by the number of times it occurred in that file.
e.g.
-----------------------------------------
Webpage: index.html
To do that I'm thinking of using regular expressions.
I'm using the following regex to find a hyper link in the html file.
Code:
/<(a|A).+(href|HREF)=\"(.+?)\">/
It outputs the whole line that contains the link. Say we have the following html code:
--------------------------------------------
<html>
<p> Here is some text before the link, the <a href = "www.google.com"> link </a> Some text after the link
</html>
--------------------------------------------
The output will be:
--------------------------------------------
Here is some text before the link, the <a href = "www.google.com"> link </a> Some text after the link
--------------------------------------------
What i need is to somehow get rid of all unnecessary output leaving the target url of a link and nothing else. So that the output would be:
I've tried using the following, however if the are several links on a line only the first link is found:
{ start = index($0, "<a")
end = index($0,"\">")
len = end - start
print substr($0,start,len) }
Hi
After lot of trial and error I am really bowled out with the requirement in hand and honestly you are my last hope
Here is what I want to achieve
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