Shell Programming and Scripting

grep pattern a.log|grep -e "p1" |cut -d":" -f1,2,3,4,8,9,10|cut -d"/" -f5 -e "p2" |cut -d":" -f1,2,3,4,6|cut -d"/" -f5 >> file

Dont know why the above command isnt working :-(

can someone correct me...

the best is to give a sample of that a.log file, and your desired output format.

Remove -e "p2"

Code:

cut -d"/" -f5 -e "p2" 

well i need that -e there as i wanna search for another pattern....do u think i need to use braces anywhere?

Change

Code:

cut -d"/" -f5 -e "p2"

to

Code:

cut -d"/" -f5 | egrep  -e "p2"

You cannot search for a pattern in cut command

If i do this
cut -d"/" -f5 | egrep -e "p2"
it will be grepping on the output because we are using the pipe....

grep pattern a.log|grep -e "p1" |cut -d":" -f1,2,3,4,8,9,10|cut -d"/" -f5 -e "p2" |cut -d":" -f1,2,3,4,6|cut -d"/" -f5 >> file

So i used the grep -e


I want to search for pattern one do the cutting part then search for pattern two and do the cutting part for that in the same log instead of grepping two times

grep pattern a.log|grep "p1" |cut -d":" -f1,2,3,4,8,9,10|cut -d"/" -f5
grep pattern a.log|grep "p2" |cut -d":" -f1,2,3,4,6|cut -d"/" -f5

i have to execute the above command by using grep only once :-)

Sorry by using grep thrice totally not four times :-)