Shell Programming and Scripting

ksh.

Hi,

I am trying to loop through the files in a directory, and process them one by one where a naming convention is met, this is fine.

As part of the looping process I need to check the first two charachters of the filename and if they are AA then perform one action, if they are XX perform a different action, I've tried the below however it doesn't seem to work. Instread of printing out a header record to the TEST_FILE of "AA" or "XX" plus the remainder of the line it is printing out "00" plus the rest of the line.


for filename in *XG.txt; do

#create header record
awk '/^0/ {if (substr($filename,1,2)=="AA") print "AA"substr($0,10,6)"00"}' $filename > TEST_FILE
awk '/^0/ {if (substr($filename,1,2)=="XX") print "XX"substr($0,10,6)"00"}' $filename > TEST_FILE

....

Code:

awk '/^0/ && FILENAME ~ /^AA/  { print "AA"substr($0,10,6)"00"}' $filename  > TEST_FILE
awk '/^0/ && FILENAME ~ /^XX/ { print "XX"substr($0,10,6)"00"}' $filename  >> TEST_FILE

??

Can you explain that a little further?
How does that compare the first two characters of the filename to match a string such as "AA"

Thanks.

I made changes to the above code. Please check the previous post.

FILENAME is an awk standard variable which holds the name of file currently processing. Here FILENAME ~ /^AA/ we are checking whether filename starts with AA.

Should it be:

awk '/^0/ && $filename ~ /^AA/ { print "AA"substr($0,10,6)"00"}' $filename > TEST_FILE
awk '/^0/ && $filename ~ /^XX/ { print "AA"substr($0,10,6)"00"}' $filename >> TEST_FILE


???

Should it be:

awk '/^0/ && $filename ~ /^AA/ { print "AA"substr($0,10,6)"00"}' $filename > TEST_FILE
awk '/^0/ && $filename ~ /^XX/ { print "XX"substr($0,10,6)"00"}' $filename >> TEST_FILE


???

have tried

awk '/^0/ && FILENAME ~ /^AA/ { print "AA"substr($0,10,6)"00"}' $filename > TEST_FILE

however there is nothing being printed out to the TEST_FILE even though the file I'm processing is named AA020507XG.txt. For some reason this is not matching the above criteria?