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# 8  
Old 05-25-2007
Quote:
Originally Posted by LiquidChild
This does not seem to work in the following though

FILE_230580.ok
FILE_230590.ok
FILE_010107.ok

As the ordering is then:

FILE_010107.ok
FILE_230580.ok
FILE_230590.ok
There are two problems :
- These files seems to be in ddmmyy format.
- The yy format is not sortable, because with this format 2007 is lower than 1980

In that case you can do something like that:
Code:
$ ls File_*
FILE_010107.ok  FILE_230580.ok  FILE_230590.ok
$ ls FILE_* | \
> awk -F_ \
>   '{
>      dd=substr($2,1,2);
>      mm=substr($2,3,2);
>      yy=substr($2,5,2);
>      print (yy<70 ? "20" : "19") yy mm dd, $0 ;
>    }' | \
> sort -k1,1 | \
> cut -d' ' -f2
FILE_230580.ok
FILE_230590.ok
FILE_010107.ok$

Jean-Pierre.
# 9  
Old 05-29-2007
What if the only yy would be above 2000, so 07, 08, 09 etc, would it make the solution simplier? If being honest its unlikely we will have a file pre 2000.
# 10  
Old 05-29-2007
Quote:
Originally Posted by LiquidChild
What if the only yy would be above 2000, so 07, 08, 09 etc, would it make the solution simplier? If being honest its unlikely we will have a file pre 2000.
Code:
ls FILE* | sort -t_ -k2.5,2.6 -k2.3,2.4 -k2.1,2.2

Jean-Pierre.
Last edited by aigles; 05-29-2007 at 08:16 AM.. Reason: Correction of typing error
# 11  
Old 05-29-2007
Thanks Jean, will give that a go, I tried using multiple keys, but have not seen the '.' notation before, what does that mean?
# 12  
Old 05-29-2007
From sort man pages :
Quote:
The -k KeyDefinition flag uses the following form:

-k [ FStart [ .CStart ] ] [ Modifier ] [ , [ FEnd [ .CEnd ] ][ Modifier ] ]

The sort key includes all characters beginning with the field specified by the
FStart variable and the column specified by the CStart variable and ending with
the field specified by the FEnd variable and the column specified by the CEnd
variable. If Fend is not specified, the last character of the line is assumed.
If CEnd is not specified the last character in the FEnd field is assumed. Any
field or column number in the KeyDefinition variable may be omitted. The default
values are:

FStart Beginning of the line

CStart First column in the field

FEnd End of the line

CEnd Last column of the field

If there is any spaces between the fields, sort considers them as separate
fields.

The value of the Modifier variable can be one or more of the letters b, d, f, i,
n, or r. The modifiers apply only to the field definition they are attached to
and have the same effect as the flag of the same letter. The modifier letter b
applies only to the end of the field definition to which it is attached. For
example:
-k 3.2b,3r


specifies a sort key beginning in the second nonblank column of the third field
and extending to the end of the third field, with the sort on this key to be
done in reverse collation order. If the FStart variable and the CStart variable
fall beyond the end of the line or after the FEnd variable and the CEnd
variable, then the sort key is ignored.
Jean-Pierre.
Last edited by aigles; 05-29-2007 at 06:24 AM..
# 13  
Old 05-29-2007
Thanks for the all the help Jean-Pierre.

I have read the above but am not clear on one thing, I get the .5 .6 which basically equates to the last two fields of the string, i.e. the year, and sorts on them first and the same for .3 .4 and .1 .2, but I don't really understand the 2. and 3. part. While I know this refers to the field and the part after the . refers to the character within the field, I don't understand how it can be 2.5 and 2.6, how are fields split up in the string, i.e. what exactly is field 2 and field 3.

Sorry I did read the above and have had a look for some further text and examples and while a bit clearer I still don't fully understand it
# 14  
Old 05-29-2007
I have corrected typing errors :
Code:
ls FILE* | sort -t_ -k2.5,2.6 -k2.3,2.4 -k2.1,2.2

With '_' as field separator, the date is field 2 is in the form ddmmyy.ok
-k2.5,2.6 : Chars 5 to 6 of field 2 -> yy
-k2.3,2.4 : Chars 3 to 4 of field 2 -> mm
-k2.1,2.2 : Chars 1 to 2 of field 2 -> dd

Jean-Pierre.
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