Shell Programming and Scripting

Hello, i'm trying to remove the ./ from this file using this SED command:

sed 's/.///g' all3.lst > all4.lst

Does anyone know the correct format for this?

For example, i'm trying to convert ./_ABMSTR.TXT.out to:
_ABMSTR.TXT.out

Thanks very much for you help on this!
BobK
./REVISED/_C5MSTR.TXT.out
./REVISED/_MCMSTR.TXT.out
./_ABMSTR.TXT.out
./_ADMSTR.TXT.out
./_AQMSTR.TXT.out
./_BAMSTR.TXT.out
./_C2MSTR.TXT.out
./_C3MSTR.TXT.out
./_C4MSTR.TXT.out
./_CBMSTR.TXT.out
./_CFMSTR.TXT.out
./_CGMSTR.TXT.out

Try this:
sed 's!./!!' input_file > output_file

Code:

echo './_ABMSTR.TXT' | sed 's#^[.]/##'

Wow that's great thanks alot all for the help, works great!

Have a great week!

BobK

Shell_Life, there are a couple of things wrong with that.

1. '.' will match ANY character so you would be replacing every occurrence of / and its preceding character with a space.
2. You didn't bind to the start of the line, so if the pattern didn't happen at the start of a line, you could make a replacement in error elsewhere.

reborg, thank you for analizing my solution.

You are absolutely right when you said that I didn't bind to the start of
the line with caract (^) -- when I tought about the solution I was only
looking at the data which every line always begins with "./".

As for the other observation, the solution does not replace "every occurrence"
of "/" in the line -- it only replaces the first one, as I didn't suffixed the "s"
command with "g" -- do you agree?

reborg, you are a real player here -- thank you.

so if the 'first occurrence' happens to be in the middle of a line/string:

Code:

$ echo '_ABMSTR./TXT' | sed 's!./!!'
_ABMSTRTXT

Yes, you do need to 'anchor' the regex to the beginning of the line.