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Shell Programming and Scripting

displaying 3 directory listings in 3 separate columns.

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Top Forums Shell Programming and Scripting displaying 3 directory listings in 3 separate columns.
# 15  
Old 04-03-2007
This will also work in perl.

Code:
#!/usr/bin/perl

$DIR1 ="dir_1";
$DIR2 ="dir_2";
$DIR3 ="dir_3";
@dir1 = `ls -1 $DIR1`;
@dir2 = `ls -1 $DIR2`;
@dir3 = `ls -1 $DIR3`;

$maxFile = scalar(@dir1);
if($maxFile < scalar(@dir2)){
        $maxFile = scalar(@dir2);
}
if($maxFile < scalar(@dir3)){
        $maxFile = scalar(@dir3);
}
        printf("%20s\t%20s\t%20s\n","$DIR1", "$DIR2", "$DIR3");
        for($i=0;$i<$maxFile;$i++)
        {
        printf("%20s\t%20s\t%20s\n","@dir1[$i]", "@dir2[$i]", "@dir3[$i]");
        }



Thanks,
Mukund Ranjan
# 16  
Old 04-04-2007
thanks munkund ranjan. coincedently i'm going to convert the script i'm writing into perl - once i've learnt the language that is.
# 17  
Old 04-04-2007
If you have Python, here's an alternative
Code:
#!/usr/bin/python
import os
a = os.listdir("/test1")
b = os.listdir("/test2")
c = os.listdir("/test3")
for item in map(None,a,b,c):
     if item[0] == None: item[0] = ''     
     if item[1] == None: item[1] = ''
     if item[2] == None: item[2] = ''
     print "%20s\t%20s\t%20s" % (item[0],item[1],item[2])
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