Help needed in character replacement in Korn Shell


 
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# 8  
Old 03-29-2007
Quote:
Originally Posted by stevefox
How do I replace a space " " character at a particular position in a line?

e.g. I have a file below

Code:
$ cat i2
111 002 A a
33 0011 B c
2222 003 C a


I want all the 1st spaces to be replaced with forward slash "/" and the 3rd spaces to have 5 spaces to get the output below:


Code:
111/002 AAA     a
33/0011 BBB     c
2222/003 CCC     b

[...]
Code:
printf "%s/%s %s%5s\n" $(<inputfile)

# 9  
Old 03-30-2007
Quote:
Originally Posted by heru_90
Code:
sed 's/ /\//;s/ \(.\)$/    \1/' file

Hi matrixmadhan, can you explain what mean your code?

Thank you


regards,

heru
following are the blocks in the code,

s/ /\// - this first substitution block replaces the first occuring space character to a forward slash, since thats a special character to nullify its special meaning precede it by a back slash

s/ \(.\)$/ - the second substitution block replaces the space and any character at the end with the below replacement below

\1/ - this would effectively replace it with 5 spaces and the selected block


Smilie
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