Shell Programming and Scripting

Hi All,
This script is not working. I want to change the directory as per users selection in current shell. Looks like it is spawning sub-shell internally.
I have used

. changedir.sh
source changedir.sh
./changedire.sh

But did not work. Currently shell directory remain the same.

Please correct my mistakes.
Thanks,
Ram

*************************
x=0
for tree in $( ls -l | grep "^d" | cut -c61- )
do
x=`expr $x + 1`
echo "$x $tree"
done
echo "Enter the view number to set or 0 to another view or q to quit"
read answer
y=0

for user in $( ls -l | grep "^d" | cut -c61- )
do
y=`expr $y + 1`
if [ $y == $answer ]; then
cd $user
echo "setting tree: $user"
fi
done
***************************

Hi,
Sometimes getting the directory name by using cut -c61- may lead to error like it may not get the directory name properly.
Try the following code to get the directory name and use your code like this
ls -l | grep ^d | cut -d: -f2 | sed 's/[0-9][0-9] //g'

x=0
#for tree in $( ls -l | grep "^d" | cut -c61- ) Instead of this use
for tree in $( ls -l | grep ^d | cut -d: -f2 | sed 's/[0-9][0-9] //g' )
do
x=`expr $x + 1`
echo "$x $tree"
done
echo "Enter the view number to set or 0 to another view or q to quit"
read answer
y=0

If my assumption is right this will solve your issue...
Thanks
Raghuram

you can use a function in your interactive shell...

here's a silly thing I use.
Put it in a file and source it and I have a CD command which
gives me a choice of my ENV directories.
(i am lazy)

Code:

function CD
{
unset list
    env | while read line;do
        var=${line%=*}
        val=${line#*=}
        [ -d $val ] && list="$list $var"
    done

    select dir in $list;do
        eval cd \$$dir
        break
    done
unset list
}

This is silly but really neat!

I am a genius you know!
(so my mum says)