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checking size of the first line in a log file

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Top Forums Shell Programming and Scripting checking size of the first line in a log file
# 8  
Old 03-22-2007
Code:
>cat test.log
0 sample_test.log

Code:
>ls -l sample_test.log
-rw-r--r--    1 user  group        226 Mar 22 03:17

Code:
>ls -l `awk -F" " 'NR == 1 { print $2; exit }' test.log` | awk '{ print $5 }'

226


the above command gives the size.
I believe this is what your expected output, if not could you please explain! Smilie
# 9  
Old 03-22-2007
Quote:
Originally Posted by matrixmadhan
how about this,

Code:
ls -l `awk -F" " 'NR == 1 { print $2; exit }' file` | awk '{ print 5 }'


should have been,
Code:
ls -l `awk -F" " 'NR == 1 { print $2; exit }' file` | awk '{ print $5 }'

oops! ' $ ' is missing
# 10  
Old 03-22-2007
Hi Matrix thx for ur reply
i m sry...i think you misunderstood me
let me be clear
my test.log contains
Code:
 
    0 190_GSTV_HUX_003QISCGSK026_errorXXXXXXXXXXXXX.log
   34 190_GSTV_HUX_003QISCGSK026_errorXXXXXXXXXXXXX.log
   12 190_GSTV_HUX_003QISCGSK026_errorXXXXXXXXXXXXX.log

now i need to check if the first column of first file is 0 or not(in this case it is 0)
and write a condition based on whether it is 0 or not
hope i am not confusing you
i tried
Code:
ls -l `awk -F" " 'NR == 1 { print $2; exit }' file` | awk '{ print $1 }'

but it is giving size of all files Smilie
Pls help
thanks in advance
# 11  
Old 03-22-2007
Code:
$ cat file
   0 190_GSTV_HUX_003QISCGSK026_error070322_115331917.log
   34 190_GSTV_HUX_003QISCGSK026_error070117_151311385.log
   12 190_GSTV_HUX_003QISCGSK026_error070117_151230001.log
   2 190_GSTV_HUX_003QISCGSK026_error070117_101010001.log
   0 190_GSTV_HUX_003QISCGSK026_error070117_0832001254.log
   0 190_GSTV_HUX_003QISCGSK026_error070115_122813125.log
   3 190_GSTV_HUX_003QISCGSK026_error070115_115331917.log
   0 190_GSTV_HUX_003QISCGSK026_error070115_114442254.log
   0 190_GSTV_HUX_003QISCGSK026_error070112_1156001509.log
$ awk 'NR==1 {print $1;exit}' file
0

try this
Code:
check=`awk 'NR==1 {print $1;exit}' /home/user/test.log`

# 12  
Old 03-22-2007
ya i tried that too ...but
Code:
awk 'NR==1 {print $1;exit}' test.log

is printing a blank line and
Code:
 awk 'NR=1{print $1}' test.log

is printing size of all files ie.,
0
34
12
0
.
.
.


Thnx
kiran
# 13  
Old 03-22-2007
Code:
awk -F" " 'NR==1 {print $1;exit}' test.log

the above should definitely work

print the first field from the file from the first line and exit
exact conversion of your requirement i believe Smilie

Could you please try that ? Smilie
# 14  
Old 03-22-2007
There might be blank lines at the start of test.log file.Remove those blank lines and use
Code:
awk 'NR==1 {print $1;exit}' test.log
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