Shell Programming and Scripting

I am on a HP-UX machine I have a directory called "/u01/blobs" and the files look like this:
ls -1
7398
7399
7400

I need to produce a comma delimited file with the following format:

filename,location/filename
i.e:
7398,/u01/blobs/7398
7399,/u01/blobs/7399
7400,/u01/blobs/7400

What I have so far is:
#!/bin/ksh
FILE_DIR=/u01/blobs
INFILE=a.txt
INFILE2=b.txt
INFILE3=c.txt

if [[ -a $INFILE ]]; then
rm $INFILE
fi

ls -1 $FILE_DIR > $INFILE

cat $INFILE | sed 's/$/,\/u01\/blobs\//w '${INFILE2} > /dev/null


But this just gives me the filename and directory.

It seams like a simple task but it is giving me a SEDache.

Regards,
NomDeGuerre

Code:

$ find /u01/blobs -type f -print | while read filename; do
>    echo "${filename##*/},${filename}" 
> done > filelist
$ cat filelist
7398,/u01/blobs/7398
7399,/u01/blobs/7399
7400,/u01/blobs/7400

Cheers
ZB

Give a try on this..
ls |sed 's!\([0-9]\{4\}\)!\1,/u01/blobs/\1!'

Output:

Code:

7395,/u01/blobs/7395
7399,/u01/blobs/7399
7400,/u01/blobs/7400

Thnx.Dennis

A slight modification..If you need it for any directory
dir_path=directory
ls $(dir_path) |sed 's!\([0-9]\{4\}\)!\1,'$dir_path'/\1!'