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replace word with using "sed" not work...

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Top Forums Shell Programming and Scripting replace word with using "sed" not work...
# 8  
Old 02-28-2007
Quote:
Originally Posted by matrixmadhan
Based on the sample file posted, command was posted.

Could you please post the exact command you ran and the output that you got? Smilie

I had tested and then only posted, sure the command should work Smilie
I just found out...one thing..because of my converting problem...

can I delete the 3rd number and move 4th number to 3rd..?

<Number>11 20 03 22 23 21 91 00 F0</Number>
<Number>12 20 03 20 99 21 91 20 F0</Number>
<Number>10 21 03 21 78 21 92 27 F0</Number>

output like
<Number>11 00 32 22 32 19 10 0F</Number>
<Number>12 00 32 09 92 19 12 0F</Number>
<Number>10 10 32 17 82 19 22 7F</Number>
# 9  
Old 02-28-2007
Code:
sed -e 's/ /g;s/\(.\{10\}\).\(.\{2\}\)\(.\{2\}\)\(.\{2\}\)\(.\{2\}\)\(.\{2\}\)\(.\{2\}\)\(.\{2\}\).\(.*\)/\1 \2 \3 \4 \5 \6 \7 \8\9/' file

# 10  
Old 02-28-2007
Quote:
Originally Posted by matrixmadhan
Code:
sed -e 's/ /g;s/\(.\{10\}\).\(.\{2\}\)\(.\{2\}\)\(.\{2\}\)\(.\{2\}\)\(.\{2\}\)\(.\{2\}\)\(.\{2\}\).\(.*\)/\1 \2 \3 \4 \5 \6 \7 \8\9/' file


Many thanks...but can you explain to me...above?
also the number is not fixed..can be 10 digits, 11 digits or 13 digits...but I just need to delete 3nd digit and move all forward..
# 11  
Old 02-28-2007
Code:
sed -e "s/ //g" -e "s/\([0-9][0-9]\)./\1/" -e "s/\([0-9][0-9]\)/\1 /g" -e "s/0</</" file

# 12  
Old 02-28-2007
Quote:
Originally Posted by sb008
Code:
sed -e "s/ //g" -e "s/\([0-9][0-9]\)./\1/" -e "s/\([0-9][0-9]\)/\1 /g" -e "s/0</</" file

thank's sb008, but I must need to delete <number> field/line of 3nd number and delete the last digit (to make all 2 digit a group)
# 13  
Old 02-28-2007
Quote:
Originally Posted by happyv
thank's sb008, but I must need to delete <number> field/line of 3nd number and delete the last digit (to make all 2 digit a group)
Code:
# cat file
<Number>11 20 03 22 23 21 91 00 F0</Number>
<Number>12 20 03 20 99 21 91 20 F0</Number>
<Number>10 21 03 21 78 21 92 27 F0</Number>

# sed -e "s/ //g" -e "s/\([0-9][0-9]\)./\1/" -e "s/\([0-9][0-9]\)/\1 /g" -e "s/0</</" file
<Number>11 00 32 22 32 19 10 0F</Number>
<Number>12 00 32 09 92 19 12 0F</Number>
<Number>10 10 32 17 82 19 22 7F</Number>

Provides exactly the output you requested.
# 14  
Old 02-28-2007
Quote:
Originally Posted by sb008
Code:
# cat file
<Number>11 20 03 22 23 21 91 00 F0</Number>
<Number>12 20 03 20 99 21 91 20 F0</Number>
<Number>10 21 03 21 78 21 92 27 F0</Number>

# sed -e "s/ //g" -e "s/\([0-9][0-9]\)./\1/" -e "s/\([0-9][0-9]\)/\1 /g" -e "s/0</</" file
<Number>11 00 32 22 32 19 10 0F</Number>
<Number>12 00 32 09 92 19 12 0F</Number>
<Number>10 10 32 17 82 19 22 7F</Number>

Provides exactly the output you requested.
but..the sed command...how can you identify <number>? because of the file not just <number> field...it also contain <serial no>, etc..
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