Shell Programming and Scripting

What abt this...? I thnk this shuold remove the '#'es and blank lines... I hvn't tested this nyway....!!
sed 's/^#//g' data_file -->will remove #es and grep -v '^$' will remove the blank lines...



for i in $(sed 's/^#//g' data_file |grep -v '^$'| awk -F" " '{print NR}')
do
nam_arr[$i]=$(awk -F" " -v cnter=$i '{ if (cnter == NR) {print $1;} }' data_file)
num_arr[$i]=$(awk -F" " -v cnter=$i '{ if (cnter == NR) {print $2;} }' data_file)
done

If the blank lines contain spaces then use this

Code:

grep -v '^ *$'

Jacoden,

The sed and grep command does not work in that script.
Still have blank lines and comment_out lines

try this

Code:

for i in $(sed '/^#/d;/^ *$/d' file| awk -F" " '{print NR}')

Oops..Just tested and corrected my mistake..Sorry abt that!!!

Here is my tested data file:
-----------------------------------------------
Mike 3434


Jack 481

Peter 12
Alan 926
#
Jacob 3423

Dennis 123


------------------------------------------------------------------------
Try for this script....


for i in $(cat data_file | sed -e 's/^#//g' -e '/^ *$/d' | awk -F" " '{print NR}')
do
nam_arr[$i]=$(cat data_file | sed -e 's/^#//g' -e '/^ *$/d' | awk -F" " -v cnter=$i '{ if (cnter == NR) {print $1;} }' )
num_arr[$i]=$(cat data_file | sed -e 's/^#//g' -e '/^ *$/d' |awk -F" " -v cnter=$i '{ if (cnter == NR) {print $2;} }' )
done

echo Array details

for i in $(cat data_file | sed -e 's/^#//g' -e '/^ *$/d' | awk -F" " '{print NR}')
do
echo nam_arr[$i]=${nam_arr[i]}
echo num_arr[$i]=${num_arr[i]}
done

-------------------------------------------------------------------
Result is shown below:

Array details
nam_arr[1]=Mike
num_arr[1]=3434
nam_arr[2]=Jack
num_arr[2]=481
nam_arr[3]=Peter
num_arr[3]=12
nam_arr[4]=Alan
num_arr[4]=926
nam_arr[5]=Jacob
num_arr[5]=3423
nam_arr[6]=Dennis
num_arr[6]=123
-----------------------------------------------------------------------
I hope there won't b "MORE" mistakes in this

Yeah, great!
Thank you all!