Shell Programming and Scripting

Code:

ls -lt

is a long listing of directory contents sorted by mod time (and a "total" at the top)

Code:

ls -lt | awk 'NR>1'

gets rid of that header line

Code:

ls -lt | awk 'NR>1 {print $9}'

displays only the ninth field(filename)

Code:

ls -lt | awk 'NR>1 {if (substr($1,1,1) == "-" ) print $9}'

displays name if the first field (like -rw-rw-r--) starts with hyphen (indicates an ordinary file)

Code:

ls -lt | awk 'NR>1 {if (substr($1,1,1) == "-" && n++ > 6) print $9}'

prints a list of file names but omits the first 7 (first = most recent)

Code:

ls -lt | awk 'NR>1 {if (substr($1,1,1) == "-" && n++ > 6) print $9}' | xargs rm

does exactly what you want

Thank you

I have to try with this one and test

thanks again
Vajiramani

hi Perderabo

Its fantastic, i achieved this by writing ten line what you did it in one line.

Thank you

Regards
Vajiramani