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How to include a variable between apostrophes within a command

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# 1  
Old 02-21-2007
How to include a variable between apostrophes within a command
Hi.

I'm trying to find some words within my directory and created a text file containing them which is read by my shell script:
Code:
#!/bin/bash
var=`cat words.txt`
for i in $var; do
	echo $i
        find -type f -print0 | xargs -r0 grep -F '$i'
done

But it searches "$i" (dollar sign with 'i'), and not the word. How to do it?

Thank you very much.
# 2  
Old 02-21-2007
Quote:
Originally Posted by guarriman
Code:
#!/bin/bash
var=`cat words.txt`
for i in $var; do
	echo $i
        find -type f -print0 | xargs -r0 grep -F '$i'
done

Code:
find -type f -print0 | xargs -r0 grep -F "$i"

# 3  
Old 03-16-2007
guarriman,
You can try:
ls -1 | egrep -f words.txt
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