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how do I filter double lines from a txt file

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Top Forums Shell Programming and Scripting how do I filter double lines from a txt file
# 8  
Old 02-20-2007
Code:
access-list 1 permit xxxxxxxxxxxxxx
access-list 1 permit xxxxxxxxxxxxxx
access-list 2 permit xxxxxxxxxxxxxx

In above sample when it reads the first line x != $2 is satisfied and 1 is assigned to x and this line is printed. In case of second line x != $2 is not satisfied and the line is not printed. In case of third line x != $2 is satisfied and 2 is assigned to x and this line is printed.
# 9  
Old 02-20-2007
I still dont understand it
# 10  
Old 02-20-2007
Can you tell what do you understand now?
# 11  
Old 02-20-2007
Quote:
Originally Posted by anbu23
Code:
access-list 1 permit xxxxxxxxxxxxxx
access-list 1 permit xxxxxxxxxxxxxx
access-list 2 permit xxxxxxxxxxxxxx

In above sample when it reads the first line x != $2 is satisfied and 1 is assigned to x and this line is printed. In case of second line x != $2 is not satisfied and the line is not printed. In case of third line x != $2 is satisfied and 2 is assigned to x and this line is printed.
First it picks up the records begining with "access-list"

after that (Note: $2 represents the second field( that is 1 for the first line))
the statement x!=$2 would be true for the first time. and then 1 is being assigned
to x so x has the value 1. when the command processes the second line then $2=1 that
means x=$2 so this time the condition fails and so nothing is printed uptill it reaches
where $2 value is 2 it would continue to skip the lines. once it has reached where $2=2
then again the condition(x!=$2) is true and the record is printed and this time 2 is
assigned to x and this continues uptill the end of file. Incase, if the record doesnt
start with "access-list" then also print the line.

I hope i am clear enough

ANBU - If i am wrong please correct me.
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