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Assign o/p of awk to a variable

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# 8  
Old 02-01-2007
Quote:
1. I thought only single slash is required for escaping, then whats the meaning of double slash.
Code:
YYYN939@CANPC-003249 ~
$ x=`awk "{ print \$0 }" f`
x=`awk "{ print \$0 }" f`
awk "{ print $0 }" f
++ awk '{ print bash }' f
+ x=

YYYN939@CANPC-003249 ~
$ x=`awk "{ print \\$0 }" f`
x=`awk "{ print \\$0 }" f`
awk "{ print \$0 }" f
++ awk '{ print $0 }' f
+ x='Hi
How are you'

YYYN939@CANPC-003249 ~
$ x=$(awk "{ print \$0 }" f)
x=$(awk "{ print \$0 }" f)
awk "{ print \$0 }" f
++ awk '{ print $0 }' f
+ x='Hi
How are you'

Quote:
2. Also why doesnt the following one work:
myvariable=`awk '/^.{232}$acctNum/ { printf("%s;Y;Account",substr($0,241,1)) ; exit} ' myinputfile.txt`
In this case we dont even need escaping.
This wont work because variable substitution wont occur inside single quotes. So this variable $acctNum wont expand.
You can use try this
Code:
awk -v no var=$acctNum ' $0 ~ "^.{232}"var { ... } ' file

or
Code:
awk '/^.{232}'"$acctNum"'/ { ... } ' file

# 9  
Old 04-01-2009
awk command result to variable
I have a similar problem by assigning a value of a command to a variable. In this case, with:
Get list of Network interfaces: /usr/sbin/networksetup -listnetworkserviceorder
Get specifically the one that contains the word "Ethernet": awk -F'\\) ' '/\Ethernet/ {print $2}'`

Assign the whole string to a variable called: "networkInterface": networkInterface= "`/usr/sbin/networksetup -listnetworkserviceorder | awk -F'\\) ' '/\Ethernet/ {print $2}'`"

Any ideas? I'm really stuck in here.Smilie
Last edited by Franklin52; 04-01-2009 at 08:56 AM.. Reason: Replace wrong color tags
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