Shell Programming and Scripting

You are getting this error because count variable is null.
Try this

Code:

if [ -n "$count" ] &&  [ $count -gt 1 ] ; then

hi anbu,

got this error below :

BASEDIR=/export/home/mapadm
BINDIR=/export/home/mapadm/bin
LOGDIR=/export/home/mapadm/log
TDRDIR=/export/home/mapadm/log/TDR
BACKUPDIR=/data/log
+ export BASEDIR BINDIR LOGDIR TDRDIR BACKUPDIR
+ date +%Y
YEAR=2007
+ date +%m
MONTH=02
+ date +%d
DAY=01
+ date +%H
HOUR=11
+ [ 11 -eq 00 ]
+ cd /export/home/mapadm/log/TDR/200701
+ expr 11 - 1
HOUR=10
+ printf %02d 10
HOUR=10
filename=2007020110.TDR
+ nawk $12 == "00008001" { cnt++;cs_cd[$11] } END { print cnt } 2007020110.TDR
nawk: can't open file 2007020110.TDR
source line number 1
count=
+ [ -n ]

please advices..

thank you so much

Regards,

bucci

Check whether the file 2007020110.TDR present in the directory /export/home/mapadm/log/TDR/200701

hi anbu,

if you review back to my script the file is present on the directory,

cd $TDRDIR/200701 -----> define to change to directory which the file logged

any idea?

thank you

Best Regards,

bucci

check whether you have read permission for that file

hi anbu,

yes have a read permission for that file :

-rw-r--r-- 1 mapadm staff 470076 Feb 1 10:59 2007020110.TDR

idea?

thank you

Regards,

bucci

Can you show the first few lines of the file?