Cut Last 3 Fields


 
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# 1  
Old 01-10-2007
Cut Last 3 Fields

I have a text:

dsj khfksjdh <time> EST 2006
ab cgnr jkkjt <time> EST 2006
gfhdgjghg <time> EST 2006
fkdjh kjhsekjrh kdjhfkh jhdfkhfdkjh kjdf <time> EST 2006


In the above file i need to extract time from every line... which is always the third from the last... Pls help!

Cheers,
Bouren
# 2  
Old 01-10-2007
If you want only the third from the last field, this should work:
Code:
awk '{print $(NF-2)}' file

If you want the last three fields, try:
Code:
awk '{print $(NF-2), $(NF-1), $NF}' file

# 3  
Old 01-10-2007
cat <filename>|awk '{print $(NF-2)}'
# 4  
Old 01-10-2007
Quote:
Originally Posted by Krrishv
cat <filename>|awk '{print $(NF-2)}'
Useless Use of Cat
# 5  
Old 01-11-2007
Code:
sed "s/.*\(<time>.*\)$/\1/" file

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