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problem with if condition

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# 1  
Old 01-10-2007
problem with if condition
hi, Smilie
pls consider the following if statement

if [ -z $(echo $1|sed 's/[0123456789]//g') ]
then
........
else
.......

when i execute the script i am getting the following error

'(' unexpected

I am not able to find the mistake.
could anybody tell where i did mistake.

cheers
RRK
# 2  
Old 01-10-2007
I can run your code in ksh without any problem:
Code:
#!/bin/ksh
if [ -z $(echo $1 | sed 's/[0-9]//g') ]; then
echo "Numeric"
else
echo "Non-Numeric"
fi

Output:
Code:
$./test 123
Numeric
$./test a123
Non-Numeric

Which shell you are using?
# 3  
Old 01-10-2007
same kornshell!
# 4  
Old 01-10-2007
I can only suggest you to check the version of ksh because i have tested your code at ksh93, if you are too at ksh93 then i'm aslo blank!!!

Regards,
Tayyab
# 5  
Old 01-10-2007
Put a
set -o
in front of the "if" statement and post the results. The output from "set -o" will settle which shell is processing that "if" statement.
# 6  
Old 01-10-2007
Try this instead and let's see:
Code:
if [ -z `echo $1|sed 's/[0123456789]//g'` ]

# 7  
Old 01-10-2007
putting back quotes also giving the same error. Smilie
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