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awk: last occurance

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# 8  
Old 01-02-2007
Quote:
Originally Posted by becket
yes, but i've edited it
I must be going blind here...
# 9  
Old 01-02-2007
vgersh99, the remaining post is confusing, but I think what happened is that the post that says "to ignore" is the only one posted, it was edit within the timelimit for not showing the edit information at the bottom.
# 10  
Old 01-02-2007
Quote:
Originally Posted by reborg
vgersh99, the remaining post is confusing, but I think what happened is that the post that says "to ignore" is the only one posted, it was edit within the timelimit for not showing the edit information at the bottom.
ah I see - I thought ALL of the edits would be reflected in the posts.
Well.... I've been wrong before.

Thanks for the clarification, reborg!
Last edited by vgersh99; 01-03-2007 at 12:43 AM..
# 11  
Old 01-03-2007
Reborg,

Whats the timelimit for the edit by the way? I think 30 minutes?
# 12  
Old 01-03-2007
Here's my sample file called test
Quote:
test1
test2
test3
test4
test5
test1:2
test2:2
test3:2
test4:2
test5:2
test1:3
test2:3
test3:3
test4:3
test5:3
To print all values matching pattern:
Code:
awk '$0~"test1"' test

or
Code:
 awk '$0~"test1"{var=$0;print var}' test

To print just the last occurence
Code:
 awk '$0~"test1"{var=$0}END{print var}' test

# 13  
Old 01-03-2007
Hi All,

vgersh99 this was the one I was after, thanks!

Code:
{                              
   lines[$2] = $0              
}                              
END {                          
    for (i in lines)           
        print lines[i]         
}

Now I realise that now that's done (duplicates removed and latest only output based on $2) I need to sort this output by the next field ($3) numerically. Any ideas?

Cheers, p.
# 14  
Old 01-03-2007
Code:
sort -t" " -kn3 file
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