Shell Programming and Scripting

Hi, pls advise how we could make change to more than one pattern in a single line using sed..

ie:

IGNORE abcd delete}}}
COND IGNORE efgh}}}

will yield in

abcd delete}}
COND IGNORE efgh}}}

Pls note that IGNORE may not be in the start of line, IGNORE is intended to be removed only if it's the first word in the line together with closed bracked at the end of the line.

Thanks.

Code:

sed '/^IGNORE.*}$/s/IGNORE//g' myFile

Hi, thanks..but there can be blanks before the first IGNORE and "}" at the end of the line need to be replaced as well....rgds.

Code:

sed '/^ *IGNORE.*} *$/s/IGNORE//g' myFile

Hi, thanks..I've got around the first blank earlier
But, i've got to replace }}} from that line to }}...so how shall a sed line does 2 pattern replace in a command...(ie IGNORE removal and } removal..)..thx.

Code:

sed 's/^ *\(IGNORE\)\(.*\)\(} *\)/\2/g' myFile

Hi, thanks...rgds.