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Printing outputs using awk.

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# 1  
Old 12-27-2006
Printing outputs using awk.
I have a output of a command like this.

the command is : bdf|sed '/^e/d'|awk '{print$2/1048576}'
output :
0
0.515625
0.481979
2
2
2
7.8125
4
2
0.488281
7.8125
3.90625
4
1.95312
1
0.488281
15.625
7.8125
5.85938
0.20417
0.00119781
0.000595093
0.000587463
0.000587463
0.835808
0.206657
0.72831
0.000587463
0.000602722
0.000587463
1.73286
79.8446
6.20604
0.00723267
4.98518

i want to print only 2 digits after . please let me know how to do that?

thanks.
# 2  
Old 12-27-2006
Code:
printf("%.2f\n", $2/1048576)

# 3  
Old 12-27-2006
The command worked great..but there is a slight change in the command ie; printf will also come inside the brazes.

thanks.
Last edited by Krrishv; 12-28-2006 at 02:58 AM..
# 4  
Old 01-09-2007
Thanks mates both the commands are working.
# 5  
Old 01-09-2007
Code:
sed 's/^.*\.\(..\)\(.*\)/\1/' filename

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