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stripping out certain charecters

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# 1  
Old 11-29-2006
Error stripping out certain charecters
we are ftping zipped up files from the development server to the production server daily.The files are in this format filename.dat.20061231.12131.gz

I have to unzip the file (i can do that with gunzip) and then strip out the timestamp after the .dat extension.

I can do something like this

print $line | awk -F"." '{ print $1,$2}' and assign it a variable and then rename the file accordingly.But thats not generic..can anyone please suggest a way to just strip of all the characters after .dat .Thanks


Mervin
# 2  
Old 11-29-2006
One way using ksh:
Code:
fn1=filename.dat.20061231.12131.gz
fn2=${fn1%.dat.*}.dat
echo $fn2
filename.dat

# 3  
Old 11-30-2006
Thanks Glenn worked perfectly ..exactly what I wanted..however I am not very clear about the logic of whats happening...is it replacing all the text starting with .dat with .dat ie .dat.20061212.1341 with .dat ...if so how do the various metacharecters work in this script...thanks so much once again..sorry about the late response
# 4  
Old 11-30-2006
You are correct. Here is how it works (this is from O'Reilly's Learning the Korn Shell; also see man ksh for more information):
Code:
Operator: ${variable#pattern}
Meaning: If the pattern matches the beginning of the variable's value, 
delete the shortest part that matches and return the rest.
 
Operator: ${variable##pattern}
Meaning: If the pattern matches the beginning of the variable's value, 
delete the longest part that matches and return the rest.
 
Operator: ${variable%pattern}
Meaning: If the pattern matches the end of the variable's value, 
delete the shortest part that matches and return the rest.
 
Operator: ${variable%%pattern}
Meaning: If the pattern matches the end of the variable's value,
delete the longest part that matches and return the rest.

# 5  
Old 12-01-2006
Thanks for the clarification
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