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Shell Programming and Scripting

string manipulation

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# 8  
Old 08-17-2007
how can we split the string based on the "\n" character in UNIX...?
Hi,

I have a korn shell string variable like with the value

str1 = "first\nsecond\nthird\lnfourth"

I would like to cut the string based on the "\n" character, wherever occur the "\n" character in the line.

how can we split the string based on the "\n" character like this...?

s1= "first"
s2="second"
s3="third"
s4="fourth"


Please help!

Thanks in advance
Siva.P
Bangalore
India.
# 9  
Old 08-17-2007
Continuing with anbu's code. use \n as the field separator.

Code:
eval `echo $str1 | awk -F"\n" '{
for (i =1; i <= NF; i++)
        printf("a[%d]=%s\n",i,$i);
}'`

# 10  
Old 08-17-2007
Hi Ahmed,

The beloew code is not generating any output.

eval `echo $str1 | awk -F"\n" '{
for (i =1; i <= NF; i++)
printf("a[%d]=%s\n",i,$i);
}'`

Regards,
Siva.P
Bangalore
India.
# 11  
Old 08-17-2007
you need to assign the value to the variable str1 before running my code
# 12  
Old 08-17-2007
help you and need your help
Try follow code:

Code:
str="a,b,c,d,e"
echo $str | awk 'BEGIN{FS=","}
{for (i=1;i<=NF;i++)
{if (i==1)
$i=sprintf("letter=|%s|",$i)
else$i=sprintf(" or letter=|%s|",$i)
}
print $0}
END{print str1}'

But i do not know how to print <'> in awk body, so i use <|> instead.

Anyone can help me on this will be very appreciate.
# 13  
Old 08-20-2007
Hi ahemad,

i have updated the above script and tested but its not generating any outputs..
See by updated code..

str1 = "first\nsecond\nthird\lnfourth"
echo "Actual Given String is : $str1"
eval `echo $str1 | awk -F"\n" '{
for (i =1; i <= NF; i++)
printf("a[%d]=%s\n",i,$i);
}'`

Thanks in Advance and help me any one.

Regards,
Siva.P
Bangalore
India.
String_Manipulation.ksh.txt (502 Bytes) 
# 14  
Old 08-20-2007
Quote:
Originally Posted by psiva_arul
Hi,

I have a korn shell string variable like with the value

str1 = "first\nsecond\nthird\lnfourth"

I would like to cut the string based on the "\n" character, wherever occur the "\n" character in the line.

how can we split the string based on the "\n" character like this...?

s1= "first"
s2="second"
s3="third"
s4="fourth"
[...]

Code:
$ s="first\nsecond\nthird\nfourth"
$ set -- $(print $s)
$ printf "\$1 is %s\n\$2 is %s\n...\n" $1 $2
$1 is first
$2 is second
...


Then you can:

Code:
$ c=1;while [ $c -le ${#@} ];do eval "s$c=\${$c}";c=$((c+1));done
$ print $s1
first
$ print $s4
fourth

Last edited by radoulov; 08-20-2007 at 12:38 PM.. Reason: Addition
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