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division operation in shell script

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# 29  
Old 10-23-2006
hi vgersh.. i put the script in debug by doing a set -x. i got these results. i would prefer doing a divide to find out the percentage load.

Code:
+ echo .15
.15
+ bc
+ echo if (                 .15 > '.95') 1
syntax error on line 1, teletype
+ [  -eq 1 ]
+ echo .15
.15
+ exit

# 30  
Old 10-23-2006
Quote:
Originally Posted by ragha81
hi vgersh.. i put the script in debug by doing a set -x. i got these results. i would prefer doing a divide to find out the percentage load.

Code:
+ echo .15
.15
+ bc
+ echo if (                 .15 > '.95') 1
syntax error on line 1, teletype
+ [  -eq 1 ]
+ echo .15
.15
+ exit

this is very strange - I have a very similar code running under Solaris 9 with no problem.

here's my sample from the previous post:
ragha.sh 35 36

ragha.sh:
Code:
#!/usr/local/bin/ksh

typeset -i num_tasks="${1}"
typeset -i max_tasks="${2}"

typeset threshold='.95'

echo "num->[$num_tasks]"
echo "max->[$max_tasks]"

per_load=$(echo "scale=2; $num_tasks / $max_tasks" | bc)

echo "per_load->[$per_load]"

if [ "$(echo "if (${per_load} > ${threshold}) 1" | bc)" -eq 1 ]; then
   echo "not good"
fi

Are you sure you have the code in YOUR script similar to what I have in my sample?

Is you script a '#!/bin/ksh' script?
# 31  
Old 10-23-2006
yes vgersh,

i have '#!/bin/ksh' script running and I have whatever you have me. not sure why this is happening..
# 32  
Old 10-23-2006
neither do I.
if you want.... check the script posted here and see if it works as a 'stand alone'. If it does, you have something mis-typed and/or something wrong in your 'main' script.
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