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How to get only the first line of output?

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Top Forums Shell Programming and Scripting How to get only the first line of output?
# 8  
Old 10-09-2006
I think you need to post the whole output and also post the output you want finally...
# 9  
Old 10-09-2006
Your suggestion works out fine, vish. Thank you. I used the one provided by Ygor but I had to pipe all the commands on one line to get what I wanted. Now I have a slightly different problem with the second function because there I need to remove the PID of the processes that I have removed in the first function. It can't be accomplished in the same way though because the PIDs are different. I guesss one way to do this is to remove the whole row with the repeating threads of the table invoked by
Code:
netstat -tuv | lsof -i

Code:
COMMAND   PID USER   FD   TYPE DEVICE SIZE NODE NAME
dhcpcd     56 root    4u  IPv4     54       UDP *:bootpc
sshd       87 root    3u  IPv4     90       TCP *:ssh (LISTEN)
psi       606 root   10u  IPv4 443233       TCP margarita.bg.nc:42904->cub.bg.nc:jabber-client (ESTABLISHED)
psi       608 root   10u  IPv4 443233       TCP margarita.bg.nc:42904->cub.bg.nc:jabber-client (ESTABLISHED)
rdesktop 7467 root    4u  IPv4 426395       TCP margarita.bg.nc:38797->tiger.bg.nc:3389 (ESTABLISHED)

If anyone has an idea how I could implement that, I would be grateful.
Code:
#!/bin/bash
showProcesses()
{
	netstat -tuv | awk '{print $1}' > ports.list
        lsof -i < ports.list | awk 'NR>1{print $1}' | uniq 
}

showNumberOfFiles()
{
	lsof -i < ports.list | awk 'NR>1{print $2}' > files.list
	while read pid; do
	lsof -p $pid | wc -l 
	done < files.list
}

showProcesses > file2.list

netstat -tuv | awk 'NR>2{print $4}' > file1.list

showNumberOfFiles > file3.list

paste file1.list file2.list file3.list

echo

Last edited by sanchopansa; 10-09-2006 at 08:45 AM.. Reason: Code Change
# 10  
Old 10-09-2006
What I have now (after removing the duplicating threads) is this:
Quote:
margarita.bg.nc:38797 dhcpcd 12
margarita.bg.nc:32768 sshd 23
margarita.bg.nc:42904 psi 56
margarita.bg.nc:43144 rdesktop 56 #this is left over from the second psi
21
And what I would like to have in the end is something that looks like this:
Quote:
margarita.bg.nc:38797 dhcpcd 12
margarita.bg.nc:32768 sshd 23
margarita.bg.nc:42904 psi 56
margarita.bg.nc:43144 rdesktop 21
# 11  
Old 10-09-2006
Quote:
Originally Posted by vish_indian
Change
to
Code:
lsof -i < ports.list | awk 'NR>1{print $1}' | sort | uniq

Just a remark:
sort | uniq is equivalent to sort -u
# 12  
Old 10-09-2006
OK, what I get now is a table like the one above generated from
Code:
 netstat -tuv | lsof -i

and I need to remove any repeated lines that start with the same process. This would solve my problem. In this case, I need to remove the second line with the psi. Does anyone have an idea how I could do this?
# 13  
Old 10-09-2006
resolved
I finally managed to solve. I used the uniq command with its -f property and now with lsof -i | uniq -f 7 the lines with the threads are deleted. Thanks to everyone who helped.
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