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How to capture 2 consecutive rows when a condition is true ?

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Top Forums Shell Programming and Scripting How to capture 2 consecutive rows when a condition is true ?
# 15  
Old 10-31-2006
Hi anbu, i have not miss out anything. Same error keeps popping up. Pls help
# 16  
Old 10-31-2006
Your code seems correct.
Try to execute the script with sh instead of csh :
Code:
#!/bin/sh

nawk '
$1 ~ "^[0-9][0-9]*$" && $NF == 0 { grp1=grp1+$(NF-1); tot1=tot1+1 }
$1 ~ "^[0-9][0-9]*c$" && $NF == 0 { grp2=grp2+$(NF-1); tot2=tot2+1 }
END {
printf("Group1\nAverage = %f \n",grp1/tot1)
printf("Group2c\nAverage = %f\n",grp2/tot2)
}' xxx.txt

Another test, put your awk program in a separate file:
Code:
$cat testing1.awk
$1 ~ "^[0-9][0-9]*$" && $NF == 0 { grp1=grp1+$(NF-1); tot1=tot1+1 }
$1 ~ "^[0-9][0-9]*c$" && $NF == 0 { grp2=grp2+$(NF-1); tot2=tot2+1 }
END {
printf("Group1\nAverage = %f \n",grp1/tot1)
printf("Group2c\nAverage = %f\n",grp2/tot2)
}
$cat testing1
nawk -f testing1.awk xxx.txt


Jean-Pierre.
# 17  
Old 10-31-2006
Hi Jean, thanks a million, it works!!
# 18  
Old 10-31-2006
Hi, Just notice something. If the input does not contain any 1st field with "c" appending to the number, it will show the below error. Notice also the average value is wrong. I think its because both line for eg 0001 contain "0" in the last field and i suppose it better not to use "0" as the reference point. i use 2nd field "tt=" instead. So i modified the main code to the below.

$1 ~ "^[0-9][0-9]*$" && $2 ~ "tt=" { grp1=grp1+$(NF-1); tot1=tot1+1 }
$1 ~ "^[0-9][0-9]*c$" && $2 ~ "tt=" { grp2=grp2+$(NF-1); tot2=tot2+1 }
END {
printf("Group1\nAverage = %f \n",grp1/tot1);
printf("Group2c\nAverage = %f\n",grp2/tot2)
}

For Example, my input is below

0001 x= 1 $-----.--.-..---.-..----..-.------ 0
0001 tt= 173 358 461 703 907 959 969 1151 1313 1876 2398 0

0002 x= 1 $-----.--.-..---.-..----..-.---------.--. 0
0002 tt= 167 353 455 698 900 952 962 1145 1306 1869 2391 0

Output will have error as shown below

Group1
Average = 2394.500000
nawk: division by zero
input record number 41, file xxx.txt
source line number 5

But how do i modify the above awk code such that when the input contains only one of each type (refering to group 1 or group 2 type only), it will not show any error ?

Thanks
Last edited by Raynon; 10-31-2006 at 09:39 PM..
# 19  
Old 10-31-2006
Code:
if(tot1 != 0 ) printf("Group1\nAverage = %f \n",grp1/tot1)
if(tot2 != 0 ) printf("Group2c\nAverage = %f\n",grp2/tot2)

# 20  
Old 10-31-2006
Quote:
Originally Posted by anbu23
Code:
if(tot1 != 0 ) printf("Group1\nAverage = %f \n",grp1/tot1)
if(tot2 != 0 ) printf("Group2c\nAverage = %f\n",grp2/tot2)

Thanks anbu!! It works just fine!
# 21  
Old 11-03-2006
Hi , Just another question. Why is it that only 2 sets of [0-9] is needed eg [0-9][0-9] instead of 4 sets that is [0-9][0-9][0-9][0-9] since it is a 4-digit number ?
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