Shell Programming and Scripting

I am at a point in my script where i need to use the find command. However i am not to familar with using it yet. Hopefully this will take care of that aparently with the correct option find can be used to list “plain” files, as distinct from directories. Something about it looking into files and taking a guess at what type of file it is. Well, i want it to display for me all the files with their sizes and for it to tell me which ones are text files.

Can anyone help me figure out how to use the find command?

thanks

can you provide full details...atleast give an example
it would be better to give solution

try

Code:

cd my/directory
find . -type f -exec file {} \; | grep 'ASCII' | awk '{print $1}' | ls -l

this command gives files
[sri]$ find . -type f -exec file {} \; | grep 'ASCII' | awk '{print $1}'
./y:
./file_name:


but this gives four files
[sri]$ find . -type f -exec file {} \; | grep 'ASCII' | awk '{print $1}' | ls -l
total 16
-rw-rw-r-- 1 upl upl 6 Sep 28 13:26 file_name
-rwxrwxrwx 1 upl upl 900 Sep 29 15:40 tt
-rwxrwxrwx 1 upl upl 79 Sep 29 16:32 x
-rwxr-xr-x 1 upl upl 74 Sep 30 15:31 y

pls check

I made some changes in previous post

find . -type f -exec file {} \; | grep 'ASCII' | awk '{print $1}' | sed 's/\.\///' | sed 's/://' > out_file

for file in `cat out_file`
do
ls -l $file
done

it is working

You could do this if you don't want to create a file:

Code:

fname=`find . -type f -exec file {} \; | grep 'ASCII' | awk -F\: '{print $1}'`
echo "$fname" | while read line
do
 ls -l "$line"
done

Use the -F\: with awk, and double quotes on vars to catch file names with spaces etc... Not recommended if you have a LARGE number of files to sort through, but work well for most apps.

hey, when using any of these ideas i continue to get an error that says

ASCII command not found, as well as the {print: command

then goes on to display a list of how grep can be used. then it displays the files.

Any ideas on why it cannot find ASCII or print??