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need help with simple awk/ksh script

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# 1  
Old 09-27-2006
need help with simple awk/ksh script
I need help finding out why this script wont run. The chmod is okay, but i get an error saying that I need '&&' on line 5.


Quote:
#! /bin/ksh

read x

for file in 'ls -al | awk '$6 == "Sep" && $7 < 18 , $6 != "Sep"'

do

mv $file ~/compressed.tar/$file
read x

done

tar -cvf compressed.tar
# 2  
Old 09-27-2006
I think you missing a single quote '
# 3  
Old 09-27-2006
it still says i need '&&' on line 5... does everything else look right?
# 4  
Old 09-27-2006
Question
here is how it looks now

Quote:
#! /bin/ksh

read x

for file in 'ls -al | awk '$6 == "Sep" && $7 < 18''

do

mv $file ~/compressed.tar/$file
read x

done

for file in 'ls al | awk '$6 != "Sep"''

do

mv $file ~/compressed.tar/$file
read x

done

tar -cvf compressed.tar
# 5  
Old 09-27-2006
try this
Code:
#! /bin/ksh
read x

for file in `ls -al | awk $6 == "Sep" && $7 < 18''`
do
mv $file ~/compressed.tar/$file
read x
done

for file in 'ls al | awk '$6 != "Sep"''
do
mv $file ~/compressed.tar/$file
read x
done

tar -cvf compressed.tar

Anyways, what are you trying to achive here??
# 6  
Old 09-27-2006
i get

Quote:
mv: 18 not found

mv: "Sep" not found

tar: Missing filenames
but no more '&&' needed in line 5... thanks for helping.
# 7  
Old 09-27-2006
Oops try this
Code:
read x

for file in `ls -al | awk '{$6 == "Sep" && $7 < "18"}'`
do
mv $file ~/compressed.tar/$file
read x
done

for file in 'ls al | awk '{$6 != "Sep"}'
do
mv $file ~/compressed.tar/$file
read x
done

tar -cvf compressed.tar sourcefilename
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