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transfer a variable in a shell script?

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# 1  
Old 09-22-2006
transfer a variable in a shell script?
Hey guys, seems I can't transfer the $ip into gawk in the following bash script, where the problem is?

#!/bin/bash
while read ip
do
gawk '$1~"$ip"' /tmp/source
done < /tmp/ip

++
cat /tmp/ip

192.16.1.1|192.168.1.2|192.168.1.3
10.1.1.1|10.1.1.2
10.8.1.0|10.8.1.1|10.8.1.2

--
cat /tmp/source
192.1.1.1 192.1.2.5 a
10.1.1.1 192.1.1.1 b
.....

Thank you!
# 2  
Old 09-22-2006
Code:
gawk '"'$1'" ~ "'$ip'"' source

# 3  
Old 09-22-2006
hello anbu23, thank you for your reply, but it does not work, I already double checked.

and btw, do you have some recommendation reading on this? transfer variable within shell script?
# 4  
Old 09-22-2006
try this
Code:
gawk -v par="$1" -v ipaddr="$ip" ' par ~ ipaddr ' source

# 5  
Old 09-22-2006
chk this link
http://www.faqs.org/faqs/computer-lang/awk/faq/
# 6  
Old 09-22-2006
hate to say this, but still it does not work.

I will dig up the link
# 7  
Old 09-22-2006
use awk. if it still doesn't work show us the trace of script
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