Shell Programming and Scripting

Dear Gurus,

I have this output file:

F1BDEV13 NTIAF101 2006/09/21 14:54:51 14:55:29 1 0560-0570 LAN
F1BDEV14 NTIAF101 2006/09/21 14:55:30 14:55:49 1 0000-0000 LAN
F1FSP001 NTIAF101 2006/09/21 14:55:51 14:55:53 1 0000-0000 LAN
F1NSP001 NTIAF101 2006/09/21 14:55:54 14:56:08 1 0000-0000 LAN

and this is my script:

awk '{if (NR==1) {print $7}}' ${log}/${date}.statuscheck.log
if ("$? != "0000-0000");
then
echo "Transmission Error Check Log File"
endif

i wanted to extract out 0000-0000 (see bold) which indicates the status of my file transmission. i

s there any other ways beside the above script which i have created?

my current script only check for the 1st line and get the output. what i want is to be able to search all the lines and extract out the result that i want. how do i modify my script? thanks.

wee

One way :

Code:

while read id1 id2 date hour1 hour2 status filler
do
   if [ "$status" = "0000-0000" ]
   then
      echo "Transmission Error ($id1 $id2)."
   fi
done ${log}/${date}.statuscheck.log

Jean-Pierre.

Code:

awk '$7 != "0000-0000" { print "Transmission Error Check Log File",$7}' filename_uroutputfile

it works!! bingo! thanks!!

hi another question...

apparently this is an error, so i would like to return a 1 instead of a 0 how do i go about doing it? thanks again

add
after print statement in awk

Exit with error status from awk program if transmission error found :

Code:

awk '
   $7 != "0000-0000" { 
      print "Transmission Error Check Log File",$7;
      sts = 1
   }
   END {
      exit sts
   }
' filename_uroutputfile
exit $?

Jean-Pierre.