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Finding part of a string

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# 1  
Old 09-20-2006
Finding part of a string
Hi I am very new to KSH programming
and need some help with finding a string in an error log

currently i am doing

cat FTP_LOG.lis | grep Warning

which gives me
Warning: Authentication failed. Remaining authentication methods: 'publickey,pas

I want to only pick up the test between the "Warning:" and the fullstop"."

Any help appreciated

cheers

DAF
# 2  
Old 09-20-2006
Try something like this :
Code:
sed '/Warning/!d;s/.*\(Warning[^.]*\.\).*/\1/' < FTP_LOG.lis

Jean-Pierre.
# 3  
Old 09-20-2006
here's one simpler, in Python:

Code:
for lines in open("FTP.lis"):
     if lines.startswith("Warning"):
         for c in lines:
              if c == '.': break
         print c,

# 4  
Old 09-20-2006
Code:
nawk -F '[:.]' '$1 == "Warning" { print $2 }' FTP_LOG.lis

# 5  
Old 09-21-2006
Thank you
reborg, aigles and ghostdog74
for your isolutions, they work a treat

Cheers
DAF
Last edited by DAFNIX; 09-21-2006 at 02:30 AM..
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