Shell Programming and Scripting

Hey,
i need to write a bash program that can run through a liste of files and then pick up the last access time and modification times and then write them to a file.
If anyone has done something like this before, please help me.

Thanks

#access time
ls -ul | grep "filename" | awk '{ print $9, $6 ,$7, $8, }' > fl
#modification time
ls -l | grep "filename" | awk '{ print $9, $6 ,$7, $8, }' >>fl

Hi, Anbu, can you explain what mean this code,
sorry I'm new in unix and want learn more about unix..

Thank you

Code:

ls -ul 

display all files and folders in current directory with last access time and pass this output to grep through pipe

Code:

grep "filename" 

searches for this filename in the output of above command and display that line if it finds the filename and pass this output to awk command thro pipe

Code:

awk '{ print $9, $6 ,$7, $8, }' 

display ninth field which is filename and then prints month , day and time of last access and redirecting this output to some file "fl"

Code:

ls -l 

display all files and folders in current directory with last modification time and pass this output to grep through pipe

ls -ul | grep "filename" | awk '{ print $9, $6 ,$7, $8, }' > fl

ls -ul |awk '/filename/{print $9, $6 ,$7, $8, }' > fl

Why bother with grep?

ls -ul |awk '!/filename/{print $9, $6 ,$7, $8, }' > fl (ignore this file)

Thanks for all the help.