Shell Programming and Scripting

try this

Code:

while read a b
do
        grep -q ".*$a.*$b.*" file2 
        if [ $? -ne 0 ]
        then
                echo $a $b
        fi
done < file1

Thanks, this also looks promising but I'm getting a syntax error for the grep and without it the output is all the lines from file1 and file2. whereas I jsut want the lines from file1.

grep: illegal option -- q
Usage: grep -hblcnsviw pattern file . . .

Cheers

instead of this

Code:

grep -q ".*$a.*$b.*" file2

use this

Code:

grep ".*$a.*$b.*" f2 >/dev/null

Close, very close..I made one change to allow for random order of a and b and random number of characters in each column. The only thing I can't figure out is why when it finds this it doesn't print it, everything else seems to work great:

file1
8 1


file2
8
808 322 011

while read a b
do
grep " .*$a.* " 2 |grep " .*$b.*" 2 >/dev/null
if [ $? -ne 0 ]
then
echo $a $b
fi
done < 1

Got it!

This works.

grep -w $a 2 |grep -w $b 2 >/dev/null

Thanks very much for your help, I appreciate it!

try this

Code:

while read a b
do
grep -w $a f2 |grep -w $b  >/dev/null
if [ $? -ne 0 ]
then
echo $a $b
fi
done < f1

Ug. Same problem with the array and the grep. If I have the following:

File1:
222 666

File2:
222 111 333
756 666 000

The entry for 222 666 should be printed because it's values are on 2 separate rows of file 2.

Thanks