Shell Programming and Scripting

Hi!

1. I have a parameter file containing path to log files. For this example both paths are the same, one is stated directly and the second using env variables.

/oracle/admin/orcl/bdump/:atlas:trc:N
${ORACLE_BASE}/admin/${ORACLE_SID}/bdump/:${ORACLE_SID}:trc:N

2. I try to parse the path names from ini file

#!/bin/bash
LOG_TARGETS="./log_targets.ini"
cat $LOG_TARGETS | while read LINE
do
case $LINE in
\#*) ;; #comment-line
*)
DIR=`echo $LINE | awk -F: '{print $1}' -`
echo $DIR
if [ ! -d $DIR ] ; then
echo "Warning: directory $DIR is not valid"
fi
esac
done

output ...

/oracle/admin/orcl/bdump/
${ORACLE_BASE}/admin/${ORACLE_SID}/bdump/
Warning: directory ${ORACLE_BASE}/admin/${ORACLE_SID}/bdump/ is not valid

I am not able to get the pathname for the second entry!
Lets check the env settings

$ echo $ORACLE_BASE
/oracle
$ echo $ORACLE_SID
atlas
$ echo ${ORACLE_BASE}/admin/${ORACLE_SID}/bdump/
/oracle/admin/orcl/bdump/

3. If I try it directly from bash

$ LINE="$ORACLE_BASE/admin/$ORACLE_SID/bdump/:${ORACLE_SID}:trc:N"
$ echo $LINE | awk -F: '{print $1}' -
/oracle/admin/orcl/bdump/

then the result is ok. (but not in the mentioned script above)

Any suggestions?

Found it!

DIR=`echo $LINE | awk -F: '{print $1}' -`
eval DIR=$DIR
echo $DIR